jquery - Push content off page -


I am setting a page with a vector sofa on the right and it will slide on the mouseover. On the left side of my goal page is my content on the left side of the sofa slide.

Do I need to complete my elements so that the slider again?

By default, will it slide on the left?

Any thoughts on this, I know that I am using animate () to take the seat out of adjusting the correct CSS property. How to do something to slide it, but it is not sure how to turn off the content slides on the left side of the page.

Example HTML structure:

New code: 

  $ (document) .ready (function () {$ ('# slidemarginleft button') (Function () {var $ marginLiefty = $ (this) .next (); $ marginLefty.animate ({margin left: parseint ($ margin lift CCS ('margin left'), 10) == 0? $ Margin lift.outwidth (): 0});});});

I say that to move the left-to-right corner to use the code above

Yes, the only way to slide elements to the page is by using fixed and / or full position (just outside making the element larger than the page).

I'm not sure that "this" will fall to the left side of the page, because I'm not sure how to set up the container. I'm sure many people will be ready to make better estimations if You want to put an example of what HTML will look like (for example jsbin.com is a good place to use)


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