python - Nested one-liner loops -


इस सवाल का पहले से ही एक उत्तर है: < / P>

  • 3 जवाब

मुझे पता है कि कैसे एक लिखना है लाइनर लूप, एक लूप के साथ, जैसे 

  रेंज (0,10) में एक्स के लिए: प्रिंट (x)

लेकिन मुझे ऐसा कुछ चाहिए 

  श्रेणी के लिए एक्स (0,10): यदि 1 == 1: प्रिंट (x)

हालांकि, यह एक त्रुटि देता है मैं इसे कैसे ठीक कर सकता हूं?

आप Py3 में 

  एक्स के लिए रेंज (0,10) में: प्रिंट (x) अगर 1 == 1 और कोई भी नहीं

आउटपुट 

  & gt; & gt; & gt; एक्स के लिए रेंज (0,10): प्रिंट (x) अगर 1 == 1 दूसरा कोई नहीं ... 0 1 2 3 4 5 6 7 8 9

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