shell - bash script: how to display output in different line -


I am trying to use a line of code to solve a problem 

  echo $ (this will print all the files in the existing file, which are new to new ones.) -

Input file but prints it in the same line: 

  file1 file2 file3 file4 ....

How can I display each file name in a file: 

 < Code> file1 file2 file3 ...

this One looks very simple, but I am searching and there is no solution. Thank you in advance.

echo and get rid of $ (...) .

Find -Mexade 1-type f -newer "$ 1" | Sed 's, \.

If you have GNU then you can change sed with -printf Action: 

  Find -Mexade 1-Type FNew "$ 1" -printf '% P \ n'

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